![]() To find the area, we will multiply all of that by the change in height, which is Δx. ![]() Now we can find the area of the trapezoid, which is the base added to double the width of the triangle (a), since the triangle is on both sides of the trapezoid. This is equal to the line from the base to the surface of the water (2 - x) divided by a, which is the width at 2-x. Set up the equation so that you divide the total height (4m) by the maximum width of this section (2m since (8m - 4m)/2, there's 2m on each side). ![]() Find the horizontal and vertical component of the hydrostatic acting on the curved surface. The water is on the right side of the curved surface AB, which is one quarter of a circle of radius 1.3m. First you need to find an area equation for the triangle section of the trapezoid where the width is increasing from 4m to 8m, keeping in mind that we're only interested in the area that is submerged in water (2m). Taking moment about A, Px12 21189.6x4+33284.546x5.1 P 21209 KN 12.
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